A) \[-5\sqrt{2}\]
B) \[5\sqrt{2}\]
C) \[-10\sqrt{2}\]
D) \[10\sqrt{2}\]
Correct Answer: A
Solution :
Given series is \[2\sqrt{2}+\sqrt{2}+0+...\] Here first term \[a=2\sqrt{2}\]and common difference\[d=\sqrt{2}-2\sqrt{2}\] \[=-\sqrt{2}\] We know \[{{T}_{n}}=a+(n-1)d\] \[\therefore \] \[{{T}_{8}}=2\sqrt{2}+7(-\sqrt{2})\] \[=-5\sqrt{2}\]
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