BCECE Engineering BCECE Engineering Solved Paper-2001

  • question_answer
    The distance between the lines \[y=mx+{{c}_{1}}\]and \[y=m\text{ }x+{{C}_{2}}\]is:

    A) \[\frac{{{c}_{1}}-{{c}_{2}}}{\sqrt{{{m}^{2}}+1}}\]                              

    B)  \[\frac{{{c}_{2}}-{{c}_{1}}}{\sqrt{{{m}^{2}}+1}}\]             

    C)         \[\frac{{{c}_{2}}\tilde{\ }{{c}_{1}}}{\sqrt{{{m}^{2}}+1}}\]              

    D)         0

    Correct Answer: C

    Solution :

    Since, lines are parallel, the distance from origin to the lines are \[{{d}_{1}}=\frac{{{c}_{1}}}{\sqrt{1+{{m}^{2}}}},{{d}_{2}}=\frac{{{c}_{2}}}{\sqrt{1+{{m}^{2}}}}\] \[\therefore \]Perpendicular distance between lines is \[{{d}_{1}}\tilde{\ }{{d}_{2}}=\frac{{{c}_{1}}\tilde{\ }{{c}_{2}}}{\sqrt{1+{{m}^{2}}}}\] Alternate Solution: Let us take the assuming point on the first line is \[(0,{{c}_{1}}).\] The perpendicular distance from point \[(0,{{c}_{1}})\] to the line \[y=m\text{ }x+{{c}_{2}}\] \[=\frac{{{c}_{1}}\tilde{\ }{{c}_{2}}}{\sqrt{1+{{m}^{2}}}}\]


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