A) 2.5
B) 2
C) 1.5
D) 3
Correct Answer: A
Solution :
Key Idea: Write electronic configuration of \[{{O}_{2}}^{+}\]according to molecular orbital theory then calculate bond order \[{{O}_{2}}^{+}=8+8-1=15\] \[=\sigma 1{{s}^{2}},\sigma {{1}^{*}}{{s}^{2}},\sigma 2{{s}^{2}},\sigma {{2}^{*}}{{s}^{2}},\sigma 2p{{z}^{2}},\pi 2p{{x}^{2}},\] \[\pi 2p{{y}^{2}},{{\pi }^{*}}2{{p}_{x}}^{1}\] Bond order \[=\frac{1}{2}\] [No. of electron in bonding molecular orbitals - No. of electron antibonding molecular orbitals] \[=\frac{1}{2}(10-5)\] \[=\frac{5}{2}=2.5\]
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