BCECE Engineering BCECE Engineering Solved Paper-2002

  • question_answer
    The conjugate base of \[{{\text{H}}_{\text{2}}}\text{PO}_{4}^{-}\]is:

    A) \[{{H}_{3}}P{{O}_{4}}\] 

    B) \[HP{{O}_{4}}^{2-}\]

    C) \[P{{O}_{4}}^{3-}\]         

    D) \[{{H}_{2}}PO{{  }_{3}}^{-}\]

    Correct Answer: B

    Solution :

    Key Idea: Conjugate acid base pair differ by \[{{\text{H}}^{\text{+}}}.\]Proton donors are acid \[\text{Acid}-{{H}^{+}}\xrightarrow{{}}\text{Base}\] \[\underset{acid}{\mathop{{{H}_{2}}P{{O}_{4}}}}\,-{{H}^{+}}\xrightarrow{{}}\underset{\text{conjugate}\,\text{base}}{\mathop{HPO_{4}^{2-}}}\,\]


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