BCECE Engineering BCECE Engineering Solved Paper-2004

  • question_answer
    A ball is thrown from a point with a speed  at an angle of projection\[\theta \].From the same point and at the same instant, a person starts running with a constant speed \[\frac{{{v}_{0}}}{2}\] to catch the ball. Will the person be able to catch the ball? If yes, what should be the angle of projection?

    A)  Yes, \[60{}^\circ \]        

    B)         Yes, \[30{}^\circ \]

    C)         No                                        

    D)         Yes, \[45{}^\circ \]

    Correct Answer: A

    Solution :

    Key Idea: Man will catch the ball if the horizontal component of velocity becomes equal to the constant speed of man, Horizontal velocity component of ball = constant speed of man i.e.,     \[{{v}_{0}}\cos \theta =\frac{{{v}_{0}}}{2}\] \[\Rightarrow \]               \[\cos \theta =\frac{1}{2}\] \[\Rightarrow \]               \[\cos \theta =\cos {{60}^{o}}\] \[\therefore \]  \[\theta ={{60}^{o}}\]


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