A) \[127{}^\circ C\]
B) \[227{}^\circ C\]
C) \[327{}^\circ C\]
D) \[673{}^\circ C\]
Correct Answer: B
Solution :
Efficiency of heat engine is given by \[\eta =1-\frac{{{T}_{2}}}{{{T}_{1}}}\] where \[{{T}_{1}}\] is the temperature of source and \[{{T}_{2}}\]is the temperature of sink. Given, \[\eta =\frac{30}{100}=0.3,\] \[{{T}_{2}}=77+273=350K,{{T}_{1}}=?\] Substituting values in the relation, we have \[0.3=1-\frac{350}{{{T}_{1}}}\] or \[\frac{350}{{{T}_{1}}}=1-0.3=0.7\] \[\therefore \] \[{{T}_{1}}=\frac{350}{0.7}=500\,K=227{{\,}^{o}}C\]
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