A) \[C{{H}_{3}}-C{{H}_{2}}-I\]and \[C{{H}_{3}}C{{H}_{2}}OH\]
B) \[C{{H}_{3}}-C{{H}_{2}}-OH\]
C) \[C{{H}_{3}}-C{{H}_{2}}-I\]
D) none of the above
Correct Answer: C
Solution :
Key Idea: Ether on reaction with excess of HI produce two molecules of alkyl halide \[\underset{\text{ethyl}\,\text{iodide}}{\mathop{\underset{2{{C}_{2}}{{H}_{5}}I+{{H}_{2}}O}{\mathop{\underset{\text{diethyl}\,\,\text{ether}}{\mathop{C{{H}_{3}}-C{{H}_{2}}}}\,-\underset{\downarrow }{\mathop{O-C{{H}_{2}}}}\,-C{{H}_{3}}+2HI}}\,}}\,\] When equimolar quantities of ether and HI are present, then one molecule of alkyl halide and one molecule of alcohol are formed.
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