A) \[Fe{{(OH)}_{3}}\]
B) \[Zn{{(OH)}_{2}}\]
C) \[Al{{(OH)}_{3}}\]
D) \[Sn{{(OH)}_{2}}\]
Correct Answer: A
Solution :
(a) Key Idea: \[Fe{{(OH)}_{3}}\]is not soluble in NaOH (b)\[Zn{{(OH)}_{2}}+NaOH\xrightarrow{{}}\underset{(soluble)}{\mathop{\underset{\text{sod}\text{.zincate}}{\mathop{N{{a}_{2}}ZnO{{}_{2}}}}\,}}\,+2{{H}_{2}}O\] (c) \[Al{{(OH)}_{3}}+NaOH\xrightarrow{{}}\underset{\text{(soluble)}}{\mathop{\underset{\text{sod}\text{.aluminate}}{\mathop{NaAl{{O}_{2}}}}\,+2{{H}_{2}}}}\,O\] (d) \[Sn{{(OH)}_{2}}+NaOH\xrightarrow{{}}\underset{(soluble)}{\mathop{\underset{sod.stannate}{\mathop{N{{a}_{2}}Sn{{O}_{2}}}}\,}}\,+2{{H}_{2}}O\]
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