BCECE Engineering BCECE Engineering Solved Paper-2004

  • question_answer
    \[1+\frac{3}{2}+\frac{5}{{{2}^{2}}}+\frac{7}{{{2}^{3}}}+....\infty \]is equal  to:

    A)  2            

    B)                         6                            

    C)  5                            

    D)         none of these

    Correct Answer: B

    Solution :

    Let \[S=1+\frac{3}{2}+\frac{5}{{{2}^{2}}}+\frac{7}{{{2}^{3}}}+...\] Given series is an AGP whose common ratio is \[\frac{1}{2}\]. \[S=1\frac{3}{2}+\frac{5}{{{2}^{2}}}+\frac{7}{{{2}^{3}}}+....\] \[\frac{1}{2}S=\frac{1}{2}+\frac{3}{{{2}^{2}}}+\frac{5}{{{2}^{3}}}+...\] ----------------------------------------------- \[\frac{1}{2}S=1+\frac{2}{2}+\frac{2}{{{2}^{2}}}+\frac{2}{{{2}^{3}}}+...\] \[=1+2\left( \frac{1}{2}+\frac{1}{{{2}^{2}}}+\frac{1}{{{2}^{3}}}+... \right)\] \[=1+2\left( \frac{1/2}{1-1/2} \right)\] \[=1+2=3\] \[\Rightarrow \]               \[S=6\]


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