A) 0
B) \[\frac{1}{2}\]
C) \[-1\]
D) 1
Correct Answer: D
Solution :
Now, \[\tan ({{10}^{o}}+{{35}^{o}})=\frac{\tan {{10}^{o}}+\tan {{35}^{o}}}{1-\tan {{10}^{o}}+\tan {{35}^{o}}}\] \[\Rightarrow \] \[\tan {{45}^{o}}=1=\frac{\tan {{10}^{o}}+\tan {{35}^{o}}}{1-\tan {{10}^{o}}\tan {{35}^{o}}}\] \[\Rightarrow \]\[\tan {{10}^{o}}+\tan {{35}^{o}}+\tan {{10}^{o}}\tan {{35}^{o}}=1\]
You need to login to perform this action.
You will be redirected in
3 sec
