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BCECE Engineering BCECE Engineering Solved Paper-2004

  • question_answer
    Remainder of \[{{x}^{64}}+\text{ }{{x}^{27}}+1\]divided by \[x+1\] is:

    A)  0            

    B)                                         1                            

    C)         2                                            

    D)         3

    Correct Answer: B

    Solution :

    Let \[f(x)={{x}^{64}}+{{x}^{27}}+1\] Put,        \[x=-1,\]we get \[f(-1)={{(-1)}^{64}}+{{(-1)}^{27}}+1\] \[=1-1+1=1\] Note: Remainder is nothing, but it is an ordinate value of the function of that point.


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