A) half of the potential energy
B) twice of the potential energy
C) one fourth of the potential energy
D) none of the above
Correct Answer: A
Solution :
Key Idea: Kinetic energy in an orbit \[=\frac{Z{{e}^{2}}}{8\pi {{E}^{o}}r}\] Potential energy in an orbit \[=\frac{Z{{e}^{2}}}{4\pi {{E}^{o}}r}\] ?(ii) Comparing Eqs. (1) and (2). \[KE=\frac{1}{2}PE\]
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