A) \[-75.3\,kJ\]
B) \[~+\,57.3\,kJ\]
C) \[-57.3\,kJ\]
D) \[+\,75.3\,kJ\]
Correct Answer: C
Solution :
Key Idea: The heat of neutralization of strong acid and strong base is constant because it is in/act heat of formation of water by \[{{H}^{+}}\]and \[O{{H}^{-}}.\]Its value is almost equal to \[-\text{ }57.3\text{ }kJ.\]
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