A) \[{{C}_{2}}{{H}_{6}}\]
B) \[C{{H}_{4}}\]
C) \[{{C}_{2}}{{H}_{4}}\]
D) \[{{C}_{2}}{{H}_{2}}\]
Correct Answer: C
Solution :
Key Idea: (i) Alkene and alkynes both react with \[KMn{{O}_{4}}\]and decolorize it. (ii) Only alkynes react with \[\text{AgN}{{\text{O}}_{\text{3}}}\text{ } & \]to give while precipitate. \[\underset{alkane}{\mathop{\underset{(a)}{\mathop{\underset{{{C}_{2}}{{H}_{6}}}{\mathop{H-\underset{H}{\overset{H}{\mathop{\underset{|}{\overset{|}{\mathop{C}}}\,}}}\,-\underset{H}{\overset{H}{\mathop{\underset{|}{\overset{|}{\mathop{C}}}\,}}}\,-H}}\,}}\,}}\,\] \[\underset{alkane}{\mathop{\underset{(b)}{\mathop{\underset{C{{H}_{4}}}{\mathop{H-\underset{H}{\overset{H}{\mathop{\underset{|}{\overset{|}{\mathop{C}}}\,}}}\,-H}}\,}}\,}}\,\] \[\underset{\text{alkene}}{\mathop{\underset{(c)}{\mathop{\underset{{{C}_{2}}{{H}_{4}}}{\mathop{H-\overset{H}{\mathop{\overset{|}{\mathop{C}}\,}}\,=\overset{H}{\mathop{\overset{|}{\mathop{C}}\,}}\,-H}}\,}}\,}}\,\] \[\underset{alkyne}{\mathop{\underset{(d)}{\mathop{\underset{{{C}_{2}}{{H}_{2}}}{\mathop{H-C\equiv C-H}}\,}}\,}}\,\] \[\therefore \] \[{{C}_{2}}{{H}_{4}}\](an alkene) reacts with \[KMn{{O}_{4}}\]and decolorizes it and does riot react with \[AgN{{O}_{3}}.{{C}_{2}}{{H}_{6}}\]and \[C{{H}_{4}}\]are alkane they do not react with \[KMn{{O}_{4}}\]and \[AgN{{O}_{3}}.\]
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