A) Acetone
B) Propanal
C) Ethanal
D) Butanal
Correct Answer: A
Solution :
Key Idea: Fehling solution is cupric ion complex with tartarate anion. Aldehydes reduce it to red precipitate. The red precipitate is chemically \[C{{u}_{2}}O\] \[\underset{(a)}{\mathop{\underset{acetone}{\mathop{C{{H}_{3}}-\overset{O}{\mathop{\overset{||}{\mathop{C}}\,}}\,-C{{H}_{3}}}}\,}}\,\] \[\underset{(b)}{\mathop{\underset{propanal}{\mathop{C{{H}_{3}}C{{H}_{2}}CHO}}\,}}\,\] \[\underset{(c)}{\mathop{\underset{ethanal}{\mathop{C{{H}_{3}}COH}}\,}}\,\] \[\underset{(d)}{\mathop{\underset{bu\tan al}{\mathop{C{{H}_{3}}C{{H}_{2}}C{{H}_{2}}CHO}}\,}}\,\] \[\therefore \]Only acetone which is ketone not an aldehyde does not give iodoform test.
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