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BCECE Engineering BCECE Engineering Solved Paper-2005

  • question_answer
    If p and q are the roots of the equation \[{{x}^{2}}+pq=(p+1)x,\], then \[q\]is equal to:

    A) \[~-1\]                   

    B)         2                            

    C)         1                            

    D)        \[-2\]

    Correct Answer: C

    Solution :

    Since, p and q are the roots of the equation \[{{x}^{2}}+pq=(p+1)x\]                 or            \[{{x}^{2}}-(p+1)x+pq=0\]                 \[\therefore \]      \[p+q=(p+1)\]                 \[\Rightarrow \]                    \[q=1\]


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