A) \[n(A)=n(B)\]
B) \[n(A)\le n(B)\]
C) \[n(A)\ge n(s)\]
D) none of these
Correct Answer: A
Solution :
Key Idea: A one-one onto mapping is a bijection mapping. Since, \[f:A\to B\]is a bijection. It means that mapping A to B is one-one onto \[\Rightarrow \]Both the sets have same number of elements \[\therefore \] \[n(A)=n(B)\] Note: Any function, which is either increasing or decreasing function that is an bijective mapping.
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