A) \[\pi {{a}^{2}}hk\,\text{sq}\,\text{unit}\]
B) \[\pi {{a}^{2}}\,\text{sq}\,\text{unit}\]
C) \[\pi ({{h}^{2}}+{{k}^{2}}-{{a}^{2}})\text{sq}\,\text{unit}\]
D) none of the above
Correct Answer: B
Solution :
As we know that area of circle \[=\pi {{r}^{2}}\] Since, radius a is given. \[\therefore \] \[A=\pi {{a}^{2}}\text{sq}\,\text{unit}\]
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