BCECE Engineering BCECE Engineering Solved Paper-2005

  • question_answer
    A body. dropped from a height \[h\]at time \[t=0\]reaches the ground at tune \[{{t}_{0}}.\]would have reached a height \[h/2\]at time:

    A) \[\frac{{{t}_{0}}}{2}\]                           

    B)         \[\frac{{{t}_{0}}}{\sqrt{2}}\]                              

    C)  \[t_{0}^{2}\]                        

    D)         \[\frac{1}{t_{0}^{2}}\]

    Correct Answer: B

    Solution :

    We have, \[h=\frac{1}{2}gt_{0}^{2}\]                               ?(i) Let \[{{t}_{1}}\]be the time taken by the body to reach a / height \[\frac{h}{2}.\]Then \[\frac{h}{2}=\frac{1}{2}gt_{1}^{2}\]\[\Rightarrow \]\[\frac{1}{4}gt_{0}^{2}=\frac{1}{2}gt_{1}^{2}\]  [from (i)] \[\Rightarrow \]    \[{{t}_{1}}=\frac{{{t}_{0}}}{\sqrt{2}}\]


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