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BCECE Engineering BCECE Engineering Solved Paper-2006

  • question_answer
    The equilibrium constant\[{{K}_{p}}\] for the reaction \[{{H}_{2}}(g)+{{I}_{2}}(g)2HI(g)\]is:

    A)  more than one                

    B)  less than one

    C)  equal to\[{{K}_{c}}\]     

    D)         zero

    Correct Answer: C

    Solution :

    \[{{H}_{2}}(g)+{{I}_{2}}(g)2HI(g)\] We know that, \[{{K}_{p}}={{K}_{c}}{{(RT)}^{\Delta {{n}_{g}}}}\] Here,     \[\Delta {{n}_{g}}=2-2=0\] \[\therefore \]  \[{{K}_{p}}={{K}_{c}}{{(RT)}^{0}}={{k}_{c}}\]


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