A) 5 m/s
B) 3 m/s
C) 1 m/s
D) 4 m/s
Correct Answer: C
Solution :
From equation of motion, we have \[s=ut+\frac{1}{2}a{{t}^{2}}\] where s is displacement, u is initial velocity, a is acceleration and c is time. When \[s=24\text{ }m,\text{ }t=4s,\] we have \[24=4u+\frac{1}{2}a{{(4)}^{2}}\] \[\Rightarrow \] \[24=4u+8a\] \[\Rightarrow \] \[6=u+2a\] ?(i) When body travels a total distance of \[24+64=88\] min 8 s, we get \[88=8u+\frac{1}{2}a{{(8)}^{2}}\] \[\Rightarrow \] \[88=8u+32a\] \[\Rightarrow \] \[11=u+4a\] ?(ii) Solving Eqs. (i) and (ii), we get \[u=1\,m/s\]
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