A) \[40\,k\Omega \]
B) \[4\,k\Omega \]
C) \[200\,\Omega \]
D) \[400\,\Omega \]
Correct Answer: D
Solution :
The term LED is abbreviated as Light Emitting Diode. It is forward-biased p-n junction which emits spontaneous radiation. Current in the circuit \[=10\text{ }mA=10\times {{10}^{-3}}\text{ }A\]and voltage in the circuit \[\text{= }6-2=4\text{ }V\] From Ohms law, \[V=IR\] \[\therefore \] \[R=\frac{V}{I}=\frac{4}{10\times {{10}^{-3}}}=400\,\Omega \]
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