A) \[3.12\times {{10}^{13}}\]
B) \[3.12\times {{10}^{3}}\]
C) \[3.1\times {{10}^{17}}\]
D) \[3.12\times {{10}^{19}}\]
Correct Answer: A
Solution :
Total energy\[/s=1000\,J\] Energy released/fission \[\text{= 200 MeV}\] \[=200\times 1.6\times {{10}^{-13}}J\] \[=3.2\times {{10}^{-11}}J\] \[\therefore \]Number of fission/s \[=\frac{1000}{3.2\times {{10}^{-11}}}\] \[=3.12\,\times {{10}^{13}}\]
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