A) \[1\times {{10}^{-9}}\,M\,HCl\]solution
B) \[1\times {{10}^{-5}}\,M\,NaOH\]solution
C) \[1\times {{10}^{-9}}\,M\,KOH\]solution
D) Both (a) and (b)
Correct Answer: B
Solution :
\[pH\]of \[{{10}^{-9}}\,M\,HCl\]will be \[<7\] (b) \[pOH\]of \[{{10}^{-5}}NaOH=-\log [O{{H}^{-}}]\] \[=-\log [1\,\times {{10}^{-5}}]\] \[=5\] \[pH+pOH=14\] \[pH=14-5=9\] (c)\[pH\]of \[{{10}^{-9}}\,M{{10}^{-9}}\,M\,KOH\]will be slightly grater than 7.
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