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BCECE Engineering BCECE Engineering Solved Paper-2008

  • question_answer
    The number of natural numbers less than 1000,  in which no two digits are repeated is

    A)  738                       

    B)         792                       

    C)  837                       

    D)         720

    Correct Answer: A

    Solution :

    The number of 1 digit number = 9            The number of 2 digit non-repeated number                      \[=9\times 9=81\] The number of 3 digit non-repeated number                                      \[=9\times {{\,}^{9}}{{P}_{2}}\]                                 \[=9\times 9\times 8=648\] \[\therefore \] Required number of ways\[=9+81+648\]                                                 \[=738\]


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