BCECE Engineering BCECE Engineering Solved Paper-2008

  • question_answer
    If the eccentricity of a hyperbola is\[\sqrt{3},\], then the eccentricity of its conjugate hyperbola is

    A) \[\sqrt{2}\]                                           

    B) \[\sqrt{3}\]                           

    C)  \[\sqrt{\frac{3}{2}}\]                          

    D)         \[2\sqrt{3}\]

    Correct Answer: C

    Solution :

    Let e and e are the eccentricities of a hyperbola and its conjugate hyperbola. We know that,                                      \[\frac{1}{{{e}^{2}}}+\frac{1}{{{(e)}^{2}}}=1\]                 \[\Rightarrow \]               \[\frac{1}{3}+\frac{1}{{{(e)}^{2}}}=1\]                 \[\Rightarrow \]               \[\frac{1}{{{(e)}^{2}}}=\frac{2}{3}\Rightarrow e=\sqrt{\frac{3}{2}}\]


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