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BCECE Engineering BCECE Engineering Solved Paper-2009

  • question_answer
    A rectangular coil of 100 turns and size \[0.1\times 0.05\] m is placed perpendicular to a magnetic field of 0.1 T. The induced emf when the field drops to 0.05 T in 0.05 s is

    A)  0.5 V     

    B)  1.0 V

    C)  1.5 V                    

    D)         2.0 V

    Correct Answer: A

    Solution :

                                    The induced emf \[e=-N\frac{\Delta \phi }{\Delta t}\] or            \[e=-\frac{N({{B}_{2}}-{{B}_{1}})A}{\Delta t}\] or            \[e=-\frac{100(0.1-0.05)\times 0.1\times 0.05}{0.05}\]                 \[e=0.5\,V\]


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