BCECE Engineering BCECE Engineering Solved Paper-2009

  • question_answer
    Two rods A and B of different materials are welded together as shown in figure. If their thermal conductivities are \[{{K}_{1}}\] and\[{{K}_{2}}\] the thermal conductivity of the composite rod will be

    A) \[2({{K}_{1}}+{{K}_{2}})\]        

    B) \[\frac{3}{2}({{K}_{1}}+{{K}_{2}})\]         

    C)        \[({{K}_{1}}+{{K}_{2}})\]              

    D)        \[\frac{1}{2}({{K}_{1}}+{{K}_{2}})\]

    Correct Answer: D

    Solution :

    Two slabs each of length d and same areas and thermal conductivities \[{{K}_{1}}\]and \[{{K}_{2}}\]are connected in parallel, then Heat current \[H={{H}_{1}}+{{H}_{2}}\] \[\frac{K(2A)({{\theta }_{1}}-{{\theta }_{2}})}{d}=\frac{{{K}_{1}}A({{\theta }_{1}}-{{\theta }_{2}})}{d}+\frac{{{K}_{2}}A({{\theta }_{1}}-{{\theta }_{2}})}{d}\] \[\Rightarrow \]               \[K=\frac{{{K}_{1}}+{{K}_{2}}}{2}\]


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