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BCECE Engineering BCECE Engineering Solved Paper-2009

  • question_answer
    Two masses \[{{m}_{1}}\] and\[{{m}_{2}}\] are suspended together by a massless spring of force constant k, as shown in figure. When the masses are in equilibrium, mass \[{{m}_{1}}\]is removed without disturbing the system. The angular frequency of oscillation of  mass \[{{m}_{2}}\] is                         

    A) \[\sqrt{\frac{k}{{{m}_{2}}}}\]                                     

    B) \[\sqrt{\frac{k}{{{m}_{1}}}}\]                     

    C) \[\sqrt{\frac{k{{m}_{1}}}{m\,_{2}^{2}}}\]                             

    D)        \[\sqrt{\frac{k{{m}_{2}}}{m_{1}^{2}\,}}\]

    Correct Answer: A

    Solution :

    With mass \[{{m}_{2}}\]alone, the angular frequency\[\omega =\sqrt{\frac{k}{{{m}_{2}}}}\]


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