BCECE Engineering BCECE Engineering Solved Paper-2009

  • question_answer
    Ethyl chloride on treatment with alcoholic alkali gives

    A) \[{{C}_{2}}{{H}_{6}}\]    

    B)         \[C{{H}_{3}}CHO\]         

    C)         \[{{C}_{2}}{{H}_{5}}OH\]             

    D)         \[C{{H}_{2}}=C{{H}_{2}}\]

    Correct Answer: D

    Solution :

    Alcoholic alkali acts as dehydrohalogenating agent. \[\underset{\text{ethyl}\,\text{chloride}}{\mathop{{{C}_{2}}{{H}_{5}}Cl}}\,\xrightarrow[\begin{smallmatrix}  -KCl \\  -{{H}_{2}}O \end{smallmatrix}]{Alc.(KOH)}\underset{\text{ethylene}}{\mathop{C{{H}_{2}}=C{{H}_{2}}}}\,\]


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