A) 1.5 m/s
B) 60 m/s
C) 0.1 m/s
D) 5 m/s
Correct Answer: C
Solution :
Force, \[F=ma\] \[a=\frac{F}{m}=\frac{5\times {{10}^{4}}}{3\times {{10}^{7}}}m/{{s}^{2}}\] \[\Rightarrow \] \[a=\frac{5}{3}\times {{10}^{-3}}m/{{s}^{2}}\] Since, \[{{v}^{2}}-{{u}^{2}}=2as\] \[{{v}^{2}}-0=2\times \frac{5}{3}\times {{10}^{-3}}\times 3\] \[{{v}^{2}}={{10}^{-2}}\] \[v=0.1\,m/s\]
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