A) \[\text{0}\text{.24 }\!\!\times\!\!\text{ 1}{{\text{0}}^{\text{-12}}}\,\text{N}\]
B) \[\text{2}\text{.4 }\!\!\times\!\!\text{ 1}{{\text{0}}^{\text{-12}}}\,\text{N}\]
C) \[\text{24 }\!\!\times\!\!\text{ 1}{{\text{0}}^{\text{-12}}}\,\text{N}\]
D) \[\text{0}\text{.024 }\!\!\times\!\!\text{ 1}{{\text{0}}^{\text{-12}}}\,\text{N}\]
Correct Answer: B
Solution :
Magnetic force, \[F=qvB\sin \theta \] \[\therefore \]\[F=(1.6\times {{10}^{-19}})\times (2\times {{10}^{7}})\times (1.5)sin{{30}^{o}}\] \[F=1.6\times {{10}^{-12}}\times 2\times 1.5\times \frac{1}{2}\] \[F=2.4\times {{10}^{-12}}N\]
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