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BCECE Engineering BCECE Engineering Solved Paper-2010

  • question_answer
    An inductive coil has a resistance of 100\[\Omega \] When an AC signal of frequency 1000 Hz is applied to the coil, the voltage leads the current by \[45{}^\circ \]. The inductance of the coil is

    A)  \[\frac{1}{10\pi }\]                                         

    B) \[\frac{1}{20\pi }\]

    C) \[\frac{1}{40\pi }\]                          

    D)        \[\frac{1}{60\pi }\]

    Correct Answer: B

    Solution :

    \[\tan \phi \text{=}\frac{{{X}_{L}}}{R}\] \[\therefore \]  \[\tan {{45}^{o}}=\frac{L\omega }{R}\] \[L=\frac{R}{\omega }=\frac{100}{2\pi \times 1000}\]     \[(\because \,tan{{45}^{o}}=1)\] \[L=\frac{1}{20\pi }\]


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