A) 0.5 A
B) 0.7 A
C) 1 A
D) 1.4 A
Correct Answer: C
Solution :
Current \[({{i}_{0}})=\frac{{{E}_{0}}}{{{X}_{L}}}\] \[\Rightarrow \] \[{{i}_{0}}=\frac{{{E}_{0}}}{L\omega }\] \[\therefore \] \[{{i}_{0}}=\frac{220\times \sqrt{2}}{1\times 2\pi \times 50}\] \[\Rightarrow \] \[{{i}_{0}}=\frac{220\times \sqrt{2}}{100\pi }=\frac{220\times \sqrt{2}}{100\times 3.14}\] \[\Rightarrow \] \[{{i}_{0}}=1A\]
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