A) 20.2 V
B) 42.4 V
C) 84.8 V
D) 106.8 V
Correct Answer: C
Solution :
From \[V={{V}_{0}}\sin \omega t\] \[V={{V}_{rms}}\sqrt{2}\sin \omega t\] After \[t=\frac{1}{720}s,\] \[V=120\sqrt{2}\sin 2\pi v\,t\] \[=120\sqrt{2}\sin 2\pi \times 60\times \frac{1}{720}\] \[=120\sqrt{2}\sin \frac{\pi }{6}\] \[=120\sqrt{2}\times \frac{1}{2}\] \[=60\sqrt{2}=84.8\,V\]
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