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BCECE Engineering BCECE Engineering Solved Paper-2010

  • question_answer
    The following equation represents induced transmutation \[_{4}B{{e}^{9}}{{+}_{2}}H{{e}^{4}}{{\xrightarrow{{}}}_{6}}{{C}^{12}}+X\] In this equation, X represents

    A)  one \[{{\beta }^{-}}\] particle                   

    B)  \[\alpha -\]particle

    C)  a positron

    D)                                         a neutron

    Correct Answer: D

    Solution :

    \[{{\,}_{4}}B{{e}^{9}}+{{\,}_{2}}H{{e}^{4}}\xrightarrow{{}}{{\,}_{6}}{{C}^{12}}+X\] From conservation of mass number, mass number of \[X=9+4-12=1.\]  Similarly, atomic number of \[X=4+2-6=0\] So, X is \[{{\,}_{0}}{{X}^{1}},\]ie, neutron \[({{\,}_{0}}n{{\,}^{1}}).\]


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