A) \[62.5\times {{10}^{-6}}\]
B) \[62.5\times {{10}^{-4}}\]
C) \[15.625\times {{10}^{-6}}\]
D) \[3.125\times {{10}^{-6}}\]
Correct Answer: A
Solution :
Given, solubility of \[A{{g}_{2}}S{{O}_{4}}=2.5\times {{10}^{-2}}M\] Let the solution of \[A{{g}_{2}}S{{O}_{4}}=x\,mol/L\,\] \[\underset{x}{\mathop{A{{g}_{2}}S{{O}_{4}}}}\,\xrightarrow{{}}\underset{2x}{\mathop{2A{{g}^{+}}}}\,+\underset{x}{\mathop{SO_{4}^{2-}}}\,\] \[{{K}_{sp}}=[A{{g}^{+}}][SO_{4}^{2-}]\] \[={{(2x)}^{2}}(x)\] \[=4{{x}^{3}}\] \[=4\times {{(2.5\,\times \,{{10}^{-2}})}^{3}}\] \[=62.5\times {{10}^{-6}}\]
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