A) nitroethane
B) methylcyanide
C) methylisocyanide
D) nitrobenzene
Correct Answer: C
Solution :
Reduction of nitroethane \[({{C}_{2}}{{H}_{5}}N{{O}_{2}}),\] methylcyanide \[(C{{H}_{3}}CN)\] and nitrobenzene \[({{C}_{6}}{{H}_{5}}N{{O}_{2}})\] gives\[{{\text{1}}^{\text{o}}}\] amine, while reduction of isocyanide gives \[{{2}^{\text{o}}}\] amine. \[C{{H}_{3}}N\underset{\to }{\mathop{=}}\,C\xrightarrow{LiAl{{H}_{4}}}\underset{{{\text{2}}^{\text{o}}}\text{amine}}{\mathop{C{{H}_{3}}NHC{{H}_{3}}}}\,\]
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