BCECE Engineering BCECE Engineering Solved Paper-2010

  • question_answer
    Find the equation of chord of \[{{x}^{2}}-{{y}^{2}}=9\]which is bisected at \[(5,-3).\]

    A)  \[5x+3y+16=0\]

    B)        \[~5x+3y-16=0\]

    C) \[~3x+5y+16=0\]

    D)  \[3x+5y-16=0\]

    Correct Answer: B

    Solution :

    The equation of chord of \[{{x}^{2}}-{{y}^{2}}=9\]or \[{{x}^{2}}-{{y}^{2}}-9=0\equiv (S)\](say) which is bisected at \[(5,-3)\] is given by \[{{s}_{1}}=T\]                 \[\Rightarrow \]\[{{(5)}^{2}}-{{(-3)}^{2}}-9=5x+3y-9\]                 \[\Rightarrow \]\[25-9=5x+3y\] \[\Rightarrow \]\[5x+3y-16=0\] which is the required equation.


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