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BCECE Engineering BCECE Engineering Solved Paper-2011

  • question_answer
    The minimum velocity of capillary waves on the surface of water is (surface tension of water is \[=7.2\,\times {{10}^{-2}}N/m\])

    A)  0.23 m/s                             

    B)  0.46 m/s

    C)  0.69 m/s             

    D)         0.92 m/s

    Correct Answer: A

    Solution :

    \[{{v}_{\min }}=\sqrt{2{{\left( \frac{Tg}{\rho } \right)}^{1/2}}}=1.414{{\left( \frac{Tg}{\rho } \right)}^{1/4}}\] \[=1.414{{\left( \frac{7.2\times {{10}^{-2}}\times 9.8}{{{10}^{3}}} \right)}^{1/4}}\] \[=0.23\,m/s\]


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