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BCECE Engineering BCECE Engineering Solved Paper-2011

  • question_answer
    The expression for total kinetic energy per unit volume of gas is

    A) \[\frac{E}{V}=\frac{P}{2}\]                          

    B) \[\frac{E}{V}=\frac{1}{3}P\]

    C) \[\frac{E}{V}=\frac{2}{3}P\]        

    D)        \[\frac{E}{V}=\frac{3}{2}P\]

    Correct Answer: D

    Solution :

    Pressure              \[p=\frac{1}{2}\frac{m{{{\bar{c}}}^{2}}}{V}\] \[\frac{1}{2}m{{\bar{c}}^{2}}=\frac{3}{2}pV\]                 \[E=\frac{3}{2}pV\] \[\frac{E}{V}=\frac{3}{2}p\]


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