BCECE Engineering BCECE Engineering Solved Paper-2011

  • question_answer
    The input resistance or a common emitter transistor amplifier, if the output resistance is \[500\,k\Omega ,\], the current gain \[\alpha \] = 0.98 and the power gain is \[6.0625\,\times {{10}^{6}},\] is

    A)  198 \[\Omega \]                             

    B) \[300\,\Omega \]

    C)  \[100\,\Omega \]                           

    D)  \[400\,\Omega \]

    Correct Answer: A

    Solution :

    Power gain \[=\] Current gain \[\times \] volume gain Volatge gain \[{{A}_{V}}=\beta \frac{{{R}_{2}}}{{{R}_{1}}}\] Also, current gain \[\beta =\frac{\alpha }{1-\alpha }=\frac{0.98}{1-0.98}=49\] \[\therefore \]  \[{{A}_{V}}=(49)\left( \frac{500\times {{10}^{3}}}{{{R}_{1}}} \right)\] Power gain \[=6.0625\times {{10}^{6}}\] \[=49\times \left( \frac{500\times {{10}^{3}}}{{{R}_{1}}} \right)\times 49\] \[\Rightarrow \]               \[{{R}_{1}}=198\,\Omega \]


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