A) diacetoneamine
B) pinacol
C) chloretone
D) propane
Correct Answer: B
Solution :
Bimolecular reduction of acetone gives \[\underset{\text{acetone}}{\mathop{C{{H}_{3}}-\underset{O}{\overset{C{{H}_{3}}}{\mathop{\underset{||}{\overset{|}{\mathop{C}}}\,}}}\,+\underset{O}{\overset{C{{H}_{3}}}{\mathop{\underset{||}{\overset{|}{\mathop{C}}}\,}}}\,-C{{H}_{3}}}}\,\] \[\xrightarrow{Mg-Hg,{{H}_{2}}O}{{H}_{3}}C\underset{\begin{smallmatrix} 2,3-\text{dimethyl-2,3-} \\ \text{butanediol}\,\text{(pinacol)} \end{smallmatrix}}{\mathop{-\underset{OH}{\overset{C{{H}_{3}}}{\mathop{\underset{|}{\overset{|}{\mathop{C}}}\,}}}\,-\underset{OH}{\overset{C{{H}_{3}}}{\mathop{\underset{|}{\overset{|}{\mathop{C}}}\,}}}\,-C{{H}_{3}}}}\,\]
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