A) T
B) 3 T
C) \[3\sqrt{3}T\]
D) 9 T
Correct Answer: A
Solution :
For a nearest satellite, the period of revolution is \[T=2\pi \sqrt{\frac{{{R}^{3}}}{GM}}\] \[=2\pi \sqrt{\frac{{{R}^{3}}}{G\frac{4}{3}\pi {{R}^{3}}\rho }}\] \[T\propto \sqrt{\frac{1}{\rho }}\] i.e., the period of revolution depends upon the density of the planet. Here, the density of the planets is same, therefore time period will be same.
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