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BCECE Engineering BCECE Engineering Solved Paper-2012

  • question_answer
    When 1 mole gas is heated at constant volume, temperature is raised from 298 K to 308K. Heat supplied to the gas is 500 J. Then which statement is correct?

    A) \[q=W=500J,\Delta U=0\]

    B)  \[q=\Delta U=500\,J,\,W=0\]

    C)  \[q=W=500\,J,\Delta U=0\]

    D)  \[\Delta U=0,q=W=-500\,J\]

    Correct Answer: B

    Solution :

    As we know that \[\Delta H=\Delta E+p\Delta V\] When \[\Delta V=0\]\[\therefore \]\[\Delta \Eta =\Delta E\] From first law of thermodynamics \[\Delta U=q+W\] In the given problem, \[\Delta H=500\,J\] \[-W=-p\Delta V,\Delta V=0\]                 So,          \[\Delta U=q=500\,J\]


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