BCECE Engineering BCECE Engineering Solved Paper-2012

  • question_answer
    A human body required the 0.01 M activity of radioactive substance after 24 h. Half-life of radioactive substanu is 6 h. Then injection of maximum activity of radioactive substance that can be injected

    A)  0.08                                      

    B)  0.04                      

    C)  0.16                      

    D)         0.32

    Correct Answer: C

    Solution :

    Remaining activity = 0.01 M after 24 h Remaining activity = Initial activity \[\times {{\left( \frac{1}{2} \right)}^{n}}\] Used half- life time \[(n)\] \[=\frac{\text{Total}\,\text{time}}{{{\text{T}}_{\text{1/2}}}}=\frac{24}{6}=4\] So, 0.01 = Initial activity \[\times {{\left( \frac{1}{2} \right)}^{4}}\] Initial activity \[=0.01\times 16=0.16\]


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