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BCECE Engineering BCECE Engineering Solved Paper-2013

  • question_answer
    Force acting upon a charged particle kept between the plates of changed capacitor is F. If one of the plates of the capacitor is removed force acting on the same particle will become

    A)  0                                            

    B)         F                            

    C)         \[\frac{F}{2}\]                                  

    D)         \[2F\]

    Correct Answer: C

    Solution :

    Electric field between the oppositely charged plates of a capacitor is twice that due to one plate. Hence, when one plate is removed, the electric force reduces to half of its earlier value.


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