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BCECE Engineering BCECE Engineering Solved Paper-2013

  • question_answer
    Identify the final product of the reaction \[BC{{l}_{3}}+N{{H}_{4}}Cl\xrightarrow[{{C}_{6}}{{H}_{5}}Cl]{140{{\,}^{o}}C}\xrightarrow{NaB{{H}_{4}}}\]?

    A) \[{{B}_{3}}{{N}_{3}}{{H}_{6}}\]

    B)                        \[{{B}_{2}}{{H}_{6}}\]                    

    C) \[NaBC{{l}_{4}}\]             

    D)        BN

    Correct Answer: A

    Solution :

    \[3BC{{l}_{3}}+3N{{H}_{4}}Cl\xrightarrow[{{C}_{6}}{{H}_{5}}Cl]{140{{\,}^{o}}C}{{B}_{3}}{{N}_{3}}{{H}_{3}}C{{l}_{3}}\] \[\xrightarrow{NaB{{H}_{4}}}\underset{\begin{smallmatrix}  \,\,\,\,\,\,\,\,\text{borazine}\,\text{or} \\  \text{inorganic}\,\text{benzene} \end{smallmatrix}}{\mathop{{{B}_{3}}{{N}_{3}}{{H}_{6}}}}\,\]


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