A) \[\frac{1}{34}\]
B) \[\frac{8}{221}\]
C) \[\frac{1}{26}\]
D) \[\frac{2}{51}\]
Correct Answer: C
Solution :
Total number of cases, \[n(s)=55{{C}_{2}}\] \[n(E)=\]The number of selection of 1 spade, 1 ace from 3 aces or selections of the ace of spade and 1 other spade. \[13{{C}_{1}}\times 13{{C}_{1}}+12{{C}_{1}}\times 11{{C}_{1}}=51\] \[\therefore \]\[P(E)=\frac{51}{51{{C}_{2}}}=\frac{1}{26}\]
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