A) \[{{273}^{o}}C\]
B) \[{{546}^{o}}C\]
C) \[{{1092}^{o}}C\]
D) \[{{819}^{o}}C\]
Correct Answer: D
Solution :
Velocity of sound in gas medium is given by \[v=\sqrt{\frac{\gamma RT}{M}}\] or \[v\propto \sqrt{T}\] or \[\frac{{{v}_{1}}}{{{v}_{2}}}=\sqrt{\frac{{{T}_{1}}}{{{T}_{2}}}}\] Here, \[{{v}_{1}}=332\,m/s,\,{{T}_{1}}=0+273=273\,K\], \[{{v}_{2}}=664\,m/s\] Hence, \[\frac{332}{664}=\sqrt{\frac{273}{{{T}_{2}}}}\] or \[\frac{1}{2}=\sqrt{\frac{273}{{{T}_{2}}}}\] or \[{{T}_{2}}=4\times 273=1092\,K\] or \[{{T}_{2}}=1092-273={{819}^{o}}C\]
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